substring

[Signo.X]

dim s as string = "123456"

is there any way where i can specify the start and end index of the string to be displayed?

for example .. if i use s.substring(0,3) will display the chars 1 2 3, but how can i do the same thing by specifying a start and end index of the string to be displayed...

thanks

signo.x

 

[JohnH]

length = endindex - startindex
s.substring(startindex,length)

 

[Raven65]

By saying s.Substring(0,3) you are specifiying the start and end index of the string to be displayed. Do you mean the start and in digit/charactor?

 

[JohnH]

By saying s.Substring(0,3) you are specifiying the start and end index of the string to be displayed.

No, you're not - you're specifying startindex and length.

 

[Signo.X]

thank you all
problem solved

 

[Raven65]

No, you're not - you're specifying startindex and length.

Ah! I knew I had to be misreading something there. Thanks for pointing it out for me!

 

[Signo.X]

Ah! I knew I had to be misreading something there. Thanks for pointing it out for me!

doesnt that work out at the end to be the same thing ?

- the start index will always be the same .
- the end index(the length i.e. the size from the start till the end)


do you agree ??
it's a bit confusing but in my case it worked exactely the same!!!

 

[JuggaloBrotha]

for Java: substring(StartIndex, EndIndex)
for VB.Net: SubString(StartIndex, Length)

so to get Java's substring to work like VB.Net's SubString:

private static String SubString(String source, int start, int length)
{
    return source.substring(start, (start + length));
}