Resolved split a textfile

[andrews]

Dear moderator,
I have the following problem.
I want to split an existing text file consisting of 1 line: "87,65,28,63,27,56,8,329" into an array myarray of strings like myarray(0) = "87",myarray(1) = "65", myarray(2) = "28" ....
The split separator is dim ch = cchar(",")
I can't find a solution
Thanks for any response
Regards
Andrews

 

[jmcilhinney]

You haven't looked very well if you can't find a solution. Read the file into a String and then use String.Split on that, like you would for any other String.

BTW, you don't need to convert a String literal to a Char when you can just use a Char literal:

Dim ch = ","c

 

[andrews]

Dear moderator,
With your advice I found the solution.
Juist two lines for that !
Thanks

 

[jmcilhinney]

Or even just one line:

Dim data = File.ReadAllText(filePath).Split(","c)

That will give you a String array. If you need actual numbers, you can incorporate that too:

Dim data = File.ReadAllText(filePath).Split(","c).Select(Function(s) Convert.ToInt32(s)).ToArray()

 

[andrews]

thanks

 

[andrews]

Sorry, moderator, now I get a new error on the code line for some existing files:

Dim text As String = File.ReadAllLines("C:\users\AndreAugust\source\repos\balto-zimmermann\allegridtextbestanden\" & "result.txt")(0)
The error is : System.IndexOutOfRangeException: 'Index was outside the bounds of the array.'

At the start I gave number for starting with an existing file, starting with 3 and ending with 27.
The choosen existing file is larger if the number is larger.
For the starting file all works fine for the numbers 3 to 9, but starting with 10 I get the error.
If number is 3 the file result.txt contains 19 items
For 9 there are 217 items
For 10 there it is with 271 items , now the error
And so on, for 27 there are 2107 items
I do not know the reason
By the way, what means (0) at the end of de code line?
Regards

 

[jmcilhinney]

Why would you be calling ReadAllLines in the first place? You specifically said that the file contains one line, I told you to read the file int "a String" and I showed how to do that in post #4. I don't know what ReadAllLines has to do with this topic and I don't know what the rest of post #6 means.