00shoe
Member
- Joined
- Oct 12, 2006
- Messages
- 20
- Programming Experience
- 3-5
Hey,
I have created a vb.net application that works on some computers and does not work on other computers.
When running on the troubled computer it produces the following error message before the form is loaded:
Application has generated an exception that could not be handled.
Process id=0x143c (5180), Thread id=0x1388 (5000).
Click OK to terminate the application
Click CANCEL to debug the application.
If I click Cancel it produced this message:
Registered JIT debugger is not available. An attempt to launch a JIT debugger with the following command resulted in an error code of 0x2 (2). Please check computer settings.
Cordbg.exe !a 0x14b0
Click on Retry to have the process wait while attaching a debugger manually.
Click on Cancel to abort the JIT debug request.
If I click on Retry it produces the same message.
I was able to trace the error back to MyBase.New(), and I was wondering if there is any way to enclose the code inside a try catch block so a better error message is produced. If anyone has an idea on what could be causing this error it would be good too
.
Thanks!
I have created a vb.net application that works on some computers and does not work on other computers.
When running on the troubled computer it produces the following error message before the form is loaded:
Application has generated an exception that could not be handled.
Process id=0x143c (5180), Thread id=0x1388 (5000).
Click OK to terminate the application
Click CANCEL to debug the application.
If I click Cancel it produced this message:
Registered JIT debugger is not available. An attempt to launch a JIT debugger with the following command resulted in an error code of 0x2 (2). Please check computer settings.
Cordbg.exe !a 0x14b0
Click on Retry to have the process wait while attaching a debugger manually.
Click on Cancel to abort the JIT debug request.
If I click on Retry it produces the same message.
I was able to trace the error back to MyBase.New(), and I was wondering if there is any way to enclose the code inside a try catch block so a better error message is produced. If anyone has an idea on what could be causing this error it would be good too
Thanks!