how to open a specific directory from VB.Net

[mariano_donati]

Hi, I need to open a directory, let's say "C:\Received Files" from a button of my application. Is it possible to do it without using windows API?.

Any tip/comment/question/info will be appreciated.
Thank you all very much.

 

[JuggaloBrotha]

well there's the FolderBrowserDialog for finding folders and there's the OpenFileDialog for finding files

but if you already know the location then you can use System.IO.Directories.Exist("C:\Received Files") to see if the folder exists or not

 

[mariano_donati]

But I don't need to know if it exists, I need to open that direcory to let the client select the file that he wants to open. I need to open the windows explorer and locate it in that specific directory, is it possible?

Regards!.

 

[JuggaloBrotha]

you can use the OpenFileDialog for this:

Dim ofd As New OpenFileDialog
With ofd
  .FileName = "C:\Received Files" 'Points it to the received files folder
  .Title = "Locate File"
  .Filter = "All Files (*.*)|*.*"
End With
If ofd.ShowDialog() <> DialogResult.Cancel Then
  'Use ofd.FileName to manipulate the file the user selected
End If

 

[mariano_donati]

Well, that would be great, but once the user has selected the file, I need to open it with its respective application. For example, if user selects a jpg image, then when he selects this file on FileDialog control then I don't need to manipulate the file in my application, but open it with the default application. So if it's an image, I want to open PhotoShop when user has selected the file, or if the file is a Microsoft Word document, then open Microsoft Word application for viewing the file.
I can imagine that doing that from my application might be a really difficult task for me. For that reason I want to know if there's a posibility to open windows explorer, and locate it in a specific directory. Just as Windows Messenger does when you receive a file... Did you see that messenger put you a link to the directory where you keep all files that you have received?, well, that's what I'm trying to do.
Thanks for your patience.

 

[mariano_donati]

It was as easy as this:

Process.Start("C:\Received files")

Thanks anyway.
Regards!.