Also, you may want to avoid using "..\..\..\picture" as a valid path. I say this because the working directory may change and a path like that would cause unexpected results.msdn said:' Usage
My.Computer.FileSystem.CopyFile(sourceFileName ,destinationFileName)
My.Computer.FileSystem.CopyFile(sourceFileName ,destinationFileName ,overwrite)
My.Computer.FileSystem.CopyFile(sourceFileName ,destinationFileName ,showUI)
My.Computer.FileSystem.CopyFile(sourceFileName ,destinationFileName ,showUI ,onUserCancel)
Dim DestinationPath As String = "C:\destination\"
Dim SourceFile As String
Dim DestinationFileName As String
If OpenFileDialog1.ShowDialog = Windows.Forms.DialogResult.OK Then
SourceFile = OpenFileDialog1.FileName
DestinationFileName = OpenFileDialog1.SafeFileName
My.Computer.FileSystem.CopyFile(SourceFile, DestinationPath & DestinationFileName)
End If