LeonLanford
Active member
- Joined
- Dec 2, 2008
- Messages
- 28
- Programming Experience
- Beginner
Hi.. I'm making program to read txt file from website by using system.net.webclient, It can work perfectly in localhost, but when I tried at the hosting, it got timeout after second or third request at
I thought the program hang, but after 2 minutes it shows error message saying timeout.. I must close the program and open it again, if I don't close the program, the remote txt file will cannot be opened again..
Is there something I can do to prevent the timout or prevent from reopening the program again to open the remote file?
Here's the code and screenshot..
Thanks..
VB.NET:
strem = WC.OpenRead(alamat_txt)
I thought the program hang, but after 2 minutes it shows error message saying timeout.. I must close the program and open it again, if I don't close the program, the remote txt file will cannot be opened again..
Is there something I can do to prevent the timout or prevent from reopening the program again to open the remote file?
Here's the code and screenshot..
VB.NET:
Try
Using WC As New System.Net.WebClient()
WC.OpenRead(alamat_view)
strem = WC.OpenRead(alamat_txt)
Using reader As New System.IO.StreamReader(strem)
WC.OpenRead(alamat_view)
strem = WC.OpenRead(alamat_txt)
Dim line As String = String.Empty
While reader.Peek >= 0
line = reader.ReadLine()
End While
End Using
End Using
Catch ex As Exception
MessageBox.Show("Server is busy.. Please try again")
End Try
Thanks..