String class methods

[bmoore]

input = "my mother is a great lady"
output = A -3, B - 0, C - 0, D - 1, E - 2

I wanted to count the number of times letter A - E is in the input srting.
How would i do that?

 

[newguy]

Sounds like homework. You need to do the work so you can learn it, here are some pointers:

1) you need to convert the string into an array of Char,
2) loop thru the array and count how many you find of each letter you are looking for.

 

[bmoore]

I can't learn if i don't know. i used index = str.IndexOf("A", index) and it only count 1 "a"

 

[newguy]

Strings are Char arrays.

Dim characters() As Char = "my mother is a great lady"
For Each c As Char In characters
  'look for the letters
Next c

 

[newguy]

What you need next are variables for counting.
1 for each letter you are looking for, then when you find a letter add 1 to that integer variable. You will need some logic like a If/Else statement or Select Case (my preference) inside your loop.

 

[bmoore]

As of now were just learning the string methods and properties. I need to count and display ther number of occurrences of letters a,b,c,d,e. by using string method and properties. I know i have to execute a do-while and select case but i just don't know what method to use.

 

[Solitaire]

Here is one way of doing it, counting one letter. You figure out how to count the rest:

sentence = "My mother is a great lady"
ch = "a"
count = 0
For x = 0 To sentence.Length - 1
If sentence.Substring(x, 1) = ch Then
count = count + 1 'same as count += 1
End If
Next x

 

[JohnH]

Dim target = "abcde".ToCharArray
Dim input = "my mother is a great lady".ToCharArray
Dim results = From x In target Select New With {.Character = x, .Count = input.Count(Function(y) y = x)}
For Each result In results
    With result
        Debug.WriteLine(String.Format("{0} : {1}", .Character, .Count))
    End With
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