How do I display the filename only with openfiledialog

[shurb]

I am trying to find out how to display only the filename of the file I wish to open without the full directory path. For example I want to open file test.txt which is located in c:\program files\windows.

In txtFilePath.text I want to display the file name only, (test.txt). Instead I can only get it to display c:\program files\windows\test.txt

Is there anything I can add to the following piece below to do so?

openFileDialog2.InitialDirectory = txtFilePath.Text
openFileDialog2.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*"
openFileDialog2.FilterIndex = 1
openFileDialog2.RestoreDirectory = False

 

[Administrator]

I think it's something like My.Computer.FileSystem.GetFileName(path and filename here)

 

[JuggaloBrotha]

System.IO.Path.GetFileName(FileName As String)
http://msdn2.microsoft.com/en-us/library/system.io.path.getfilename(vs.80).aspx

There's also:
System.IO.Path.GetFileNameWithoutExtension(FileName As String)

For when you need the file name but are saving it as a different type of file