Question Getting an image into a DataGrid

[gchq]

I have tried every which way to get an image into a DataGrid... Any ideas where I am going wrong?

Thanks

(I know the variable is called DGV - winforms habit, but it is a WPF DataGrid)

Public Class DGVx
        Inherits DataGrid
        Public Overrides Sub BeginInit()
            MyBase.BeginInit()
           
        End Sub
        Protected Overrides Sub OnInitialized(e As System.EventArgs)
            MyBase.OnInitialized(e)
            HorizontalAlignment = Windows.HorizontalAlignment.Stretch
            VerticalAlignment = Windows.VerticalAlignment.Stretch
            CanUserAddRows = False
            CanUserDeleteRows = False
            IsReadOnly = True
            UnselectAll()
            UnselectAllCells()
            CurrentItem = Nothing
            AlternatingRowBackground = RowColours(True)
            GridLinesVisibility = DataGridGridLinesVisibility.None
            Margin = New Thickness(3)

        End Sub
    End Class

Private Sub ImagesItems_LoadData_Completed(ByVal sender As Object, ByVal e As ReturnDataSetHASCompletedEventArgs)
        Try
            If Not e.Cancelled Then
                Dim DGV As CustomControl.DGVx = ImagesItemsGrid.FindName("ImagesItems_DGV")
                Dim DS As DataSet = e.Result
                Dim DT As DataTable = DS.Tables(0).Copy
                'Configure for images in DGV
                Dim vDT As New DataTable
                With vDT.Columns
                    .Add("ID", GetType(Integer))
                    .Add("Name", GetType(String))
                    .Add("Description", GetType(String))
                    .Add("Image", GetType(Image))
                End With



                For Each Row As DataRow In DT.Rows
                    With vDT.Rows
                        Dim ImageData As Byte() = DirectCast(Row("Image_Icon"), Byte())
                        Dim vImage As New Image
                        Dim vBitMap As New BitmapImage
                        Using vStream As New IO.MemoryStream(ImageData)
                            vImage.Source = BitmapFrame.Create(vStream, BitmapCreateOptions.None, BitmapCacheOption.OnLoad)
                        End Using
                        vImage.Height = 20
                        .Add(Row("Image_ID"), Row("Image_Name"), Row("Image_Description"), vImage)

                    End With
                Next
                DT.Dispose()

                For Each Col As DataColumn In vDT.Columns
                    Dim vDataType As String = Col.DataType.ToString

                    Select Case vDataType
                        Case "System.Int32"
                            DGV.Columns.Add(New DataGridTextColumn With {.Header = Col.ColumnName, .Binding = New Binding(String.Format("[{0}]", Col.ColumnName))})

                           


                        Case "System.Windows.Controls.Image"

                            Dim ImageCol As New DataGridTemplateColumn
                            ImageCol.Header = Col.ColumnName
                            Dim vFactory As New FrameworkElementFactory(GetType(Image))
                            Dim vBinding As New Binding(String.Format("[{0}]", Col.ColumnName))
                            vBinding.Mode = BindingMode.OneWay
                            vFactory.SetValue(Image.SourceProperty, vBinding)

                            Dim vCellTemplate As New DataTemplate
                            vCellTemplate.VisualTree = vFactory
                            ImageCol.CellTemplate = vCellTemplate
                            DGV.Columns.Add(ImageCol)

                            'DGV.Columns.Add(New DataGridTemplateColumn With {.Header = Col.ColumnName, .

                        Case Else
                            ' DGV.Columns.Add(New DataGridTextColumn With {.Header = Col.ColumnName, .Binding = New Binding(String.Format("[{0}]", Col.ColumnName))})
                            Dim DGTC As New DataGridTextColumn
                            With DGTC
                                .Header = Col.ColumnName
                                .Binding = New Binding(String.Format("[{0}]", Col.ColumnName))
                            End With
                            DGV.Columns.Add(DGTC)
                    End Select
                Next

               

                DS.Dispose()
                DGV.DataContext = vDT
                DGV.ItemsSource = vDT.DefaultView
                            
            End If
        Catch ex As Exception
            EmailError(ex)
        End Try
    End Sub

 

[gchq]

The Answer

Turns out the answer is to leave the 'image' as Byte()...

               Case "System.Byte[]"

                            Dim ImageTemp As New DataTemplate
                            Dim ImageCol As New DataGridTemplateColumn
                            Dim vFactory As New FrameworkElementFactory(GetType(Image))
                            Dim vBinding As New Binding(Col.ColumnName)
                            vFactory.SetBinding(Image.SourceProperty, vBinding)
                            ImageTemp.VisualTree = vFactory
                            ImageCol.CellTemplate = ImageTemp
                            DGV.Columns.Add(ImageCol)