Format question

[juggernot]

K, I need a number formated so it has no decimal places, and that it rounds down. how do i do that?

 

[Raven65]

Give this a shot:

Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        Dim myDec As Decimal = 9.75453
        Dim myInt As Integer = 0

        myInt = CInt(Decimal.Floor(myDec))
End Sub

 

[juggernot]

nevermind. I just needed to use integer division.

 

[JuggaloBrotha]

Math.Round(myDec, 2) would work as well

 

[Raven65]

Math.Round(myDec, 2) would work as well

Sounds like Jugger found something else, though I'm not quite sure what is meant in this reference to "Integer Division" but...either way, in this case I dont think Math.Round(myDec,2) would work would it?

Aside from the replacing the 2 with a 0 to achive the no decimal places he mentioned, is there a way to have Math.Round always round down? Seems like AwayFromZero and NearestEven are the only options.

 

[JuggaloBrotha]

Math.Floor (might be Math.ToFloor) rounds down to the nearest whole number (droppes the decimal altogether) just like Math.Ceiling rounds up to the next whole number [which actually it does this: Math.Round(YourNumber + 0.499999, 0) to get the next whole number]

one thing to remember is that Math.Round uses true rounding (statistical rounding) which means if it hits a 5 it'll round to the next even number, IE:
.5 rounds to 0
1.5 rounds to 2
2.5 rounds to 2
3.5 rounds to 4
etc....

 

[juggernot]

If you use \ instead of /, it will round your answer down, without decimal places. My teacher told me that its called integer division.

 

[Raven65]

Ah, gotcha. I think I recall something about that now, I was picturing something -completly- different =) Sorry for the confusion.

 

[cjard]

Conversion to an Integer (floating point truncation) would be what programmers call it..

Dim i as integer = 5 \ 2

or

Dim i as Integer = Convert.ToInt32(5 / 2)