I have a form which has has a bound data source (generated automatically by VB - table adapter, binding source etc).
How do I use the Form.Show method to open the form ready to enter a new record. Is there a simple way of doing this?
i've dev a program that access to an mdb database and insert a new record with the command INSERT INTO but when i execute the db command with ExecuteNonQuery the program catch an exception that i did not understand.
I post the oledbcommand line and the fields of the access mdb...